area of triangle ABC is congurent to area of triangle QRP where, area of triangle ABC/area of triangle QRP=9/4, where BC=15cm, Then find PR?
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A(∆ABC) / A(∆QRP) = BC² / PR²
9/4= 15² / PR²
PR² = 9 × 225 / 4
Taking roots on botl side we get ..,..
PR = 3 × 15 / 4
= 45 / 4
= 11.25 units
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