Question

Sides of a triangle are in ratio of 12:17:25. It's perimeter is 540cm. Find it's area by Heron's formula.
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Answer 1

$\huge \bf \red{ \mid{ \overline{ \underline{ANSWER}}} \mid}$


$\bf{QUESTION}$

Sides of a triangle are in ratio of 12:17:25. It's perimeter is 540cm. Find it's area by



$\bf{step \: by \: step \: explanation}$

let the sides of triangle be x

then

its perimeter is=540 cm

perimeter of. triangle =sum of all sides

12x+17x+25x=540

5454x=540


x=540/54

x=10

put the value of. x

12x=12*10=120

17x=17*10=170

25x=25*10=250

heron's formula. 

= first we find s

s=a+b+c/2

or

perimeter /2

s=540/2

s=270

$\sqrt{s(s - a)(s - b)(s - c)}$


$\sf{ \sqrt{270(270 - 120)(270 - 170)(270 - 250)} }$


$\sqrt{270(150)(100)(20)}$ 


$\sqrt{81000000}$ 

$\bf{9000 \: cm ^{2} }$ 



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Answer 2

Hope it helpss...☺

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