Question

arey yr pls bta do plss​

Answer 1

Two water taps together can fill a tank in 9 hours 36 minutes. The tap of larger diameter takes 8 hours less than the smaller one to fill the tank separately. Find the time in which each tap can separately fill the tank separately

let the smaller diameter tap alone fill the tank in x hours...

and larger diameter tap fill it in x-8 hours

so

when they work toghether

smaller tap fills 1/ x in one hour

larger tap fills 1/ x -8 in one hour

toghether they fill in

1 /x + 1/(x-8) in one hour..

time taken by both = 9 hours 36 min

= 9 + 36/60 hours ( and by cancelling )

= 9 + 3/5

both toghether fills it in

93/5 hours ( change into mixed fraction)

= 48 /5 hours

there from data given

1/x + 1/ x-8 = 5 /48 ( it is reversed as it is 1/x and 1/ x-8)

by calculating

5x2 -136x + 384 =0

x =(136 + or - 104 ) /10

= x = 24 or x = 16 /5 ( 16/5 is rejected as both toghether takes 9 and 36 / 60 hours to fill the tank toghether..)

x = 24 hours (smaller tap)

bigger tap = x- 8 = 16 hours

smaller tap takes 24 hours whereas bigger tap takes 16 hours..

hope it helps..