Question

arrange 3root2,2root3,root15,4 in ascending order

Answer 1

Answer:

root15,4, 2root 3,3root2

Answer 2

Answer:

2$\sqrt{3}$ < $\sqrt{15}$ < 4 < 3$\sqrt{2}$

Step-by-step explanation:

if x  < y

then $x^{2}$ < $y^{2}$

therefore for checking ascending order we will square all the numbers

=> (3$\sqrt{2}$)^2 = 18

   (2$\sqrt{3}$ )^2 = 12

    $\sqrt{15}$^2 = 15

and 4^2 = 16

as 12 < 15 < 16 < 18

therefore 3$\sqrt{2}$ < $\sqrt{15}$ < 4< 2$\sqrt{3}$

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