Arrange the following polymers in decreasing order of their intermolecular forces:
Bakelite, Polythene, Buna-S, Nylon-6,6
Arrange the following polymers in decreasing order of their intermolecular forces:
Bakelite, Polythene, Buna-S, Nylon-6,6
Answers
Answered by
2
Answer:
Hence the decreasing order of intermolecular forces is-
Bakelite > Nylon-6,6> Polythene > Buna-S
Explanation:
As we know that elastomers (Buna-S) have weak intermolecular forces, fibres (Nylon-6,6) have dipole-dipole interaction, thermoplastics (Polythene) have intermolecular forces intermediate between elastomers and fibres and thermosetting polymers (Bakelite) undergoes permanent change on heating.
Answered by
0
Answer:
Nylon - 6,6 is the correct answer
Explanation:
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