Ashwin has 8 pens. Some are blue and the others are black. He bought them for rs42. Each of the blue pen costs 4 and each blacks pen costs 6.how many pens of...
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So,
Let the no. of blue pens be x and black pens be 8 - x.
There fore,
4x + 6 (8-x) = 42
4x + 48 - 6x = 42
-2x = 42-48
2x = 6
x = 3
Therefore no. of blue pens = x = 3
No. Of black pens = 8-x = 8-3=5
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Let the no. of blue pens be x and black pens be 8 - x.
There fore,
4x + 6 (8-x) = 42
4x + 48 - 6x = 42
-2x = 42-48
2x = 6
x = 3
Therefore no. of blue pens = x = 3
No. Of black pens = 8-x = 8-3=5
Please follow me for more answers
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