Assume that in your hand you hold an ordinary six-sided die and a dime. you toss both the die and the dime on a table.
a. what is the probability that a head appears on the dime and a six on the die?
b. what is the probability that a tail appears on the dime and any number more than 3 on the die?
c. what is the probability that a number larger than 2 appears on the die?
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a. probablity of Dime is and probablity of dice is
b. probablity of Dime is and probablity of dice is
c. probablity of dice is
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Answer:
Step-by-step explanation:
a) probability of head appearing on the die is ½
probability of a six on the die is 1/6
as P(A⋂B)=P(A)P(B)
so we have,
1/2×1/6=1/12
b) probability of tail appearing on the die is ½
probability of any number more than 3 on the die is 3/6
so we have
1/2×3/6=1/4
c) 1/6+1/6+1/6+1/6=4/6=2/3
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