Assume that the earth goes round the sun in a circular orbit with a constant speed of 30 kms
(a) The average velocity of the earth from 1st jan, 90 to 30th June, 90 is zero.
(b) The average acceleration during the above period is 60 km/s2.
(c) The average speed from 1st Jan, 90 to 31st Dec, 90 is zero.
(d) The instantaneous acceleration of the earth points towards the sun.
Answers
Answer:
Assume that the earth goes round the Sun in a circular orbit with a constant speed of 30 km/s.
(a) the average velocity of the earth from 1st Jan, 90 to 30th June, 90 is zero.
(b) the average acceleration during the above period is 60 km/s².
(c) the average speed from 1st Jan, 90 to 31st Dec, 90 is zero.
(d) the instantaneous acceleration of the earth points towards the sun.
Explanation:
Since during the mentioned period in (a) and (b) the earth covers a semi circle and there is a displacement between original point to final point, so average velocity can not be zero.
Acceleration is the rate of change of velocity, here the change in velocity may be 30-(-30)=60 km/s but the time taken is six months i.e. 181*24*60*60 s. Dividing the change in velocity by this time will give the quotient much much less than 60 km/s².
Since the earth moves with a constant speed of 30 km/s, so average speed will also be 30 km/s not zero.
Since it is a case of uniform circular motion, the tangential component of the instantaneous acceleration will be zero and only radial component will be there which is directed towards the center (Sun in this case). Only option (d) is correct.
Answer: The instantaneous acceleration of the earth points towards the sun.
Read more on Brainly.in - https://brainly.in/question/5357159#readmore
The earth goes round the sun in a circular orbit with a constant speed of 30 kms then the instantaneous acceleration of the earth points towards the sun.
Explanation:
Since during the referenced period in (a) and (b) the earth covers a semi hover and there is a dislodging between unique point to definite point, so normal speed can’t be 0.
acceleration is the rate of progress of speed, here the adjustment in speed might be 30-(- 30)= 60 km/s yet the time taken is a half year for example 181*24*60*60 s. Separating the adjustment in speed at this point will give the remainder a whole lot under 60 km/s².
Since the earth moves with a steady speed of 30 km/s, so normal speed will likewise be 30 km/s not zero.
Since it is an instance of uniform round movement, the unrelated part of the prompt increasing speed will be zero and just outspread segment will be there which is coordinated towards the middle (Sun for this situation.
Therefore, the correct answer is (d) The instantaneous acceleration of the earth points towards the sun.