Question

A scooter weighing 150 kg together with its rider moving at 36 km/hr is to take a turn of a radius 30 m. What horizontal force on the scooter is needed to make the turn possible?

Answer 1

Answer:

Mass, m=150 kg ,

Speed, v=36

km/hr =36000 m/3600

s =10 m/s

Radius, r = 30 m

Force needed to make the turn possible = mv²/r =150x10x10/30 = 500 N

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Im not sure about the other part

Answer 2

500 N horizontal force on the scooter is needed to make the turn possible.

Explanation:

Given

A scooter weighing (mass) = m = 150 killogram  

Its rider moving at 36 km/hr

Speed (v) = 36 km /hr  

Converting km / hr to meter per second  

$\mathrm{Km} / \mathrm{hr}=\frac{36000 \mathrm{m}}{3600 \mathrm{s}}$

Speed (v) = 10 m/s  

Radius, r = 30 m    

Horizontal force on the scooter is needed to make the turn possible $=\frac{m v^{2}}{r}$

Put the given values in above equation,

$\begin{aligned}&=\frac{150 \times 10^{2}}{30}\\\\&=\frac{150 \times 10 \times 10}{30}\\\\&=\frac{150 \times 100}{30}\\\\&=\frac{15000}{30}\end{aligned}$

= 500 N Horizontal force on the scooter is needed to make the turn possible