Assuming complete dissociation, calculate the pH of the given solution: 0.003 M HCI
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On assuming the complete dissociation, calculate the pH of the given solution: 0.003 M HCI. The answer is 0.003 M HCl
HCl + H2O ↔ H+ + Cl-
Since HCl is completely dissociate
[H+] = HCl ,
Then, [H+] = 0.003
therefor, pH = -log [H+] = -log [0.003] = 2.52. Hence it is solved
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