Assuming complete dissociation, calculate the pH of the given solution: 0.005 M NaOH
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On assuming complete dissociation, calculate the pH of the given solution: 0.005 M NaOH solution is that 0.005 M NaOH.
NaOH ↔ Na+ + OH- [OH-] = NaOH,
[OH-] = 0.005
pOH = -log [OH-] = -log [0.005] = 2.30
Therefore, pH = 14 - 2.30 = 11.70 hence the solution is solved respectively
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Answer:
The pH of 0.005M - NaOH solution is 11.7
hope it helped you ✨
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