Question

Assuming complete ionization, same moles of which of the
following compounds will require the least amount of acidified
KMnO₄ for complete oxidation [2015 RS]
(a) FeSO₄ (b) FeSO₃
(c) FeC₂O₄ (d) Fe(NO₂)₂

Answer 1

FeSO4 is the correct option.

Explanation:

• Oxidation of a substance by an oxidising agent leads to the oxidation of the substance and reduction of the oxidising agent.

• Here KMnO4 is the oxidising agent  which gets reduced to Mn2+.

• So the number of electrons involved is 5.

• In case of the FeSO₄, Fe2+ gets oxidised to Fe3+.

• So electron involved is 1.

• In case of FeSO₃, Fe2+ gets oxidised to Fe3+ and sulphite gets oxidised to sulphate.

• So electrons involved is $1+2$ = 3.

• In case of FeC₂O₄, Fe2+ gets oxidised to Fe3+ and oxalate gets oxidised to carbon dioxide.

• So electrons involved is $1+2$ = 3.

• In case of Fe(NO₂)₂, Fe2+ gets oxidised to Fe3+ and nitrite gets oxidised to nitrate.

• So electrons involved is $1+4$ = 5.

• So least number of electrons involved is in ferrous sulphate.

• So least amount of KMnO4 will be required to get the job done.

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Define oxidation and reduction reaction on the basis of oxidation number theory and electron transfer theory