Question

At a certain temperature Kw of water is 10-10, then pH
of pure water at same temperature is
4
5
7
10​

Answer 1

Answer:

5

Explanation:

Kw=(h+)(oh-)

in water (h+)=(oh-)

so, 10-10=(h+)*2

(h+)=10-5

ph= -log (h+) = -log(10-5) =5

Answer 2

Explanation:

Answer is at attachment