Question

at a height of 15m from ground velocity of a projectile is v=10i+10j . here j , is vertically upwards and i is along horizontal direction then (g=10meter per second)​

Answer 1

$\huge\mathfrak\pink{\underline{\underline{AnSwer}}}$

Given,

V = 10i + 10j

means Vx = 10

and Vy = 10

for x - component.
.
velocity remains unchanged I.e

Ux = Vx = 10

for y - component ,

(apply equation of motion )

Vy^2 = Uy^2 + 2ah

100 = Uy^2 - 2*10* 15

Uy^2 = 400

Uy = 20

Now, tan Theta = Uy/Ux = 20/10

Theta = tan^-1 *2

Happy to help !!

:)

Answer 2

so the answer is option b,d

b)time of flight of projectile is 4sec

d)maximum height of projectile from ground is 20m