Question

At a point on level ground, the angle of elevation on the vertical tower is found to be such that its tangent is 5/12. on walking 192mts towards the tower, the tangent of the angle is found to be 3/4, find the height of the tower

Answer 1

first case:-
tan@=5/12 = height of tower /distance (d) ---------------(1)

second case:-
3/4 = height of tower /(d-192)-------(2)

from equation (1) and (2)

3 (d-192)/4=5d/12
9 (d-192)=5d
9d - 1728=5d
4d=1728
d=432 m

now
height of tower =5 x 432/12 =5 x 36=180 m

Answer 2

Plzzzzzzz mark it as brainliest