Question

Find the 17th term from the end of the AP: 1, 6, 11, 16….. 211, 216 please answer it with explanation

Answer 1

here
first term =1
common difference=6-1=5
now,
use formula ,
tn=a+(n-1) d
216 =1+(n-1) 5
215/5=n-1
n=44

hence 44 terms in this series
so, from last 17th term=from first (44-17+1) th term = 28th term from first

now,
28th term=a+(28-1) d
=1+27 x 5 =136

Answer 2

so we have that the last term of this A.P is 216
so let the last term be a that is 216 = a
so d = -5

therefore ,
an = a + (n-1)d
a17 = 216 + (17-1)(-5)
a17 = 216 - 80
a17 = 136

therefore the last seventeenth term of this AP will be 136....
u should remember the fact that a AP from the back als forms an AP...

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