Question

at a railway junction train starts from 5 diff platform at 3,4,12 ,8 and 15 min intervals when will 5 trains start together again​

Answer 1

Answer:

Let the average spped of the second train be x km/h.

Thus, the speed of the first train will be (x+5) km/h.

Distance travelled by the first train in two hours =2(x+5) km/h

Distance travelled by the second train in two hours =2x km/h

Using pythagoras theorem, we have

4x

2

+4(x+5)

2

=50

2

4x

2

+4x

2

+40x+100=2500

8x

2

+40x−2400=0

x

2

+5x−300=0

(x−15)(x+20)=0

x=15,−20

Ignore the negative value of the speed. We have,

Speed of the second train be 15 km/h.

Spped of the first train be (15+5)= 20 km/h.

Answer 2

Answer:

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Step-by-step explanation:

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