Question

At an examination in which full marks were 500. a got 10% less than b, b got 25% more than c and c got 20% less than

d. if a got 360marks, what percentage of full marks was obtained by d?

Answer 1

Full marks =500
Then
A got 10℅less than b
A got 360
So
360*10/100
36
So
B got 360+36=396
Then
B got 25℅ more than c
So
B=396
396*25/100
99
So
C got 396-99=297
Then
C got 20℅ less than d
So100
got 297
So
297*20/100
59
D got 297+59=356
Then
D got 356
356/500*100
71.2 ℅





I hope this will help you
By DEVANSH

Answer 2

Percentage

Full marks of examination $=500$

As per given information,

• A got $10\%$ less than B.

• B got $25\%$ more than C.

• C got $20\%$ less than what D got.

• A got 360 marks.

Hence, B got $(100+10)\%$ of A or 110% of A.

So , marks that B got is $\frac{110}{100}\times 360=396$

Hence B got 396 marks.

If B gets 25% more than that of C, which means,

C got the $(\frac{3}{4})\times 100=75\% \ marks \ of\ B$

$\implies marks \ obtained\ by \ C =\frac{75}{100}\times 396=297$

Hence C got 297 marks.

Marks obtained by D will be 120% of the marks obtained by C,

$\imples \frac{120}{100}\times 297=356.4$

Hence D got 356.4 marks, which is $\frac{356.4}{500}\times100=71.28 \%$.

Hence D got 71.28% of full marks.