At constant pressure, the volume of a gas is 500L at 300k. What is the volume of the gas if temperature is increased to 600k. Use the equation V/T =a constant.
Answers
Answer:
V1/T1=CONSTANT
V1=500L T1=300K T2=600K
V2 =V1/T1^T2
V2=500/300^600
V2=1000L
Explanation:
Given :
▪ Initial volume = 500L
▪ Initial temperature = 300K
▪ Final temperature = 600K
[Pressure remains constant]
To Find :
▪ Final volume of gas.
Concept :
☞ This question is completely based on the concept of charles' law.
☞ As per this law : Pressure remaining constant, the volume of a fixed mass of a gas is directly proportional to its absolute temperature.
Mathematically,
❍ V1/T1 = V2/T2
where,
V1 = Initial volume of gas
T1 = Initial temperature of gas
V2 = Final volume of gas
T2 = Final temperature of gas
Calculation :
→ V1/T1 = V2/T2
→ 500/300 = V2/600
→ V2 = (500×600)/300
→ V2 = 500×2
→ V2 = 1000L
Extra Dose :
❇ Boyle's law : At constant temperature, the pressure of a fixed amount of fas varies inversely proportional with its volume.
[P1V1 = P2V2]
❇ Gay Lussac's law : At constant volume, pressure of a fixed amount of a gas varies directly with the temperature.
[P1/T1 = P2/T2]