Question

at present asha's age is 2 more than the square of a Daughter Nisha 's age.when nisha grows to her mother present age Asa Would Be One year Less than 10 times the present age of Nisha find the present ages of both asha and nisha

Answer 1

Let Nisha's age is x years
Aisha's age = (x² + 2) years

Now, A/C to question , when Nisha grows to her mother present age .means Nisha's grows = Aisha's present age - Nisha's present age = x² + 2 - x
Then, this time Aisha's age = Aisha's present age + growing time = x² + 2 + x² + 2 - x = 2x² - x + 4

Now, question said , Aisha's age = 10× times of Nisha's age -1
2x² - x + 4 = 10x -1
2x² - 11x + 5 = 0
2x² -10x - x + 5 = 0
x = 5 and 1/2 x ≠ 1/2 because age doesn't in moths

Hence , Nisha's present age = 5 years
Aisha's present age = (5)² + 2 = 27 years


Old mark brainlest

Answer 2

Answer:

Let, Nisha’s present age be = x year

Therefore, according to the first condition, Asha's present age = x2 + 2

Nisha grows to her mother's present age after [(x² + 2) – x] years.

Then, Asha's age will become (x² + 2) + [(x² + 2) –x] years.

• According to the question :

⟹ (x² + 2) + [(x² + 2) – x] = 10x – 1

⟹ 2x² – x + 4 = 10x – 1

⟹ 2x² – 11x + 5 = 0

⟹ 2x² – 10x – x + 5= 0

⟹ 2x (x – 5) –1(x – 5) = 0

⟹ (x – 5) (2x – 1) = 0

⟹ (x – 5) = 0 or (2x – 1) = 0

⟹ x = 5 or 1/2

Ignoring x = 1/2 because then Asha’s age = x² + 2 = which is not possible.

Hence, Present Age of Nisha = 5 years

And Present Age of Asha = x² + 2 = (5)² + 2 = 25 + 2 = 27 years