Question

At what height above the surface of earth,
acceleration due to gravity reduces by 1%?​

Answer 1

Answer:

g' = g - g/100 = 0.99 g

0.99g = g(1-2h/R)

R= 6400 km

2h/6400 = 0.01

2h = 64

h = 32 km

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Answer 2

Answer:

• 0.99 = 1 - 2h/R
• 0.01 = 2h/R
• 2h/6400 = 0.01
• 2h= 64
• h= 32 km

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