Question

IS
(c)1/
(d) 18
58. The letters of word “RADHIKA” are permuted are arranged
in alphabetical order as in English dictionary. The number
of words the appear before the word "RADHIKA” is :
(a) 2193
(b)2195
(d) 2192
(c)2119​

Answer 1

the answer is(b) 2195.

Answer 2

Correct option is (a) 2193

Given word is RADHIKA

Total alphabets = 7 with 'A' repeated twice

• No. of words starting with A  :- A______ = 6! =720

• No. of words starting with D :- D______ =  $\frac{6!}{2!}$ = 360

       Divided by 2! as A alphabet is repeated twice

• No. of words starting with H :- H______ = $\frac{6!}{2!}$ = 360

       Divided by 2! as A alphabet is repeated twice

• No. of words starting with I :-  I______ =  $\frac{6!}{2!}$ = 360

       Divided by 2! as A alphabet is repeated twice

• No. of words starting with K :- K______ =  $\frac{6!}{2!}$ = 360

       Divided by 2! as A alphabet is repeated twice

Therefore total numbers of words starting from A,D,H,I,K,A =

720+360+360+360+360 = 2160

• Now comes the alphabet R :-

        Word with starting order RAA____= 4! = 24

        Word with starting order RADA___ = 3! = 06

        Word with starting order RADHA__ = 2! = 02

        Word with starting order RADHIA_ = 1! = 01

        So after above all the words, "RADHIKA" will be there.

Therefore total number of words before RADHIKA = 2160+24+06+02+01

                                                                                   = 2193