Question

at what point does the graph of the linear equation 2 X + 3 Y equal to 9 need a line which is parallel to y-axis at a distance of 4 units from the origin and on the right of the y-axis

Answer 1

two lines are
L1 : 2x+3y=9
L² : x=4

then x coordinat of point where they meet is 4

8+3y=9
y=1/3

point of interestion is (4,1/3)

hope it helps you

Answer 2

Answer:

The intersection point of the lines is $(4,\frac{1}{3})$.

Step-by-step explanation:

We are given that,

Equation of line A is, $2x+3y=9$

Equation of line parallel to y-axis is, $x=4$

It is required to find the point where these two lines intersect.

On substituting the value x = 4 in the equation of line A, we get,

$2\times 4+3y=9$

i.e. $8+3y=9$

i.e. $3y=1$

i.e. $y=\frac{1}{3}$

So, the intersection point of the lines is $(4,\frac{1}{3})$.