Question

At what rate percent will a sum of rupees 4000 yield a compound interest of rupees 410 in 2 years

Answer 1

Given, Principal = 4000, CI = 410, Time n = 2 years.

(i)

We know that A = P + CI

⇒ 4000 + 410

⇒4410.

(ii)

We know that A = P(1 + r/100)^n

⇒ 4410 = 4000(1 + r/100)^2

⇒ (4410/4000) = (1 + r/100)^2

⇒ (21/20)^2 = (1 + r/100)^2

⇒ 21/20 = 1 + r/100

⇒ (21/20) - 1 = r/100

⇒ 1/20 = r/100

⇒ 100 = 20r

⇒ r = 5.

Therefore, rate of interest = 5%.

Hope it helps!

Answer 2

Answer:

THE RATE OF INTEREST WILL BE 5%

Step-by-step explanation:

AS AMOUNT=PRINCIPAL(1+R/100)^T

4410=4000(1+R/100)^2

4410/4000=(1+R/100)^2

(21/20)^2=(1+R/100)^2

(21/20)-1=R/100

1/20=R/100

R=100/20

RATE =5%

HOPE IT HELPS