at what rate percent will the sum of rupees 1,000 amount to rupees 1102.50 in 2 years at compound interest
Answers
Answered by
60
Principal = rs. 1000
Amount = rs. 1102.50
Time = 2years
Amount = P ( 1+R/100 )^T
1102.50 = 1000 (1+R/100 )^2
1102.50/1000 = (1+R/100)^2
110250/100000 = (1+R/100)^2
441/400 = (1+R/100)^2
√441/400 = (1+R/100)
21/20 = 1+R/100
21/20-1 = R/100
R/100 = 1/20
R = 1/20 * 100
R = 5% p.a.
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Answered by
22
Answer:
Amount = P ( 1+R/100 )^T
1102.50 = 1000 (1+R/100 )^2
1102.50/1000 = (1+R/100)^2
110250/100000 = (1+R/100)^2
441/400 = (1+R/100)^2
√441/400 = (1+R/100)
21/20 = 1+R/100
21/20-1 = R/100
R/100 = 1/20
R = 1/20 * 100
Therefore ,R = 5% p.a.
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