Math, asked by sweetheart24, 11 months ago

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Answered by Panzer786
4
Radius of cylindrical glass ( R ) = 5/2 cm.


Height of cylindrical glass (H ) = 10 cm.

Radius of hemispherical part ( r ) = 5/2 cm.



Apparent Capacity of the glass = Volume of cylindre.




=> πR²H


=> ( 3.14 × 5/2 × 5/2 × 10 ) cm³.



=> ( 196.25 ) cm³.


Volume of hemispherical part = 2/3 πR³



=> ( 2/3 × 3.14 × 5/2 × 5/2 × 5/2 ) cm³.




=> ( 196.25/6 ) cm³.




=> 32.708 cm³ ~ 32.71 cm³.


Therefore,


Actual capacity of the glass = apparent Capacity of the glass - Volume of the hemispherical part.


=> ( 196.25 - 32.71 ) cm³.


=> 163.54 cm³.
Answered by Anonymous
3
*Apparent capacity of glass = volume of cylindcer

* Actually capacity of glass = volume of glass - volume of hemisphere

VOLUME. OF. CYLINDER. =====>

GIVEN

inner diameter of glass = 5cm

so radius = diameter / 2

=>5/2

=>2.5 cm

HEIGHT = 10cm

VOLUME OF CYLENDERCAL. GLASS

=>π r²h


=>3.14 × (2.5)×10

=>196.25 cm^3

VOLUME OF HEMISPHERE ==>

2/3πr^3

=>2/3 × 3.14×(2.5)

=>32.7 cm^3

Actually capacity of glass = Total volume of cylinder
- Volume of hemisphere

=>196.25-32.7

=>163.54 cm^3


Apperant capacity of glass = 196.25 cm^3
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