Question

Atomic number of Al is 13 and mass number is 27. Calculate its number of electrons, protons and neutrons in the Al3+. Represent the distribution of electrons in ion. What will be the valency of Al?​

Answer 1

Answer:

of neutrons = 27 - 13 = 14. And neutrons are=27 - 13 = 14. Hence, we can conclude that number of electrons, protons and neutrons in the ion formed is 10, 13, 14 . The ion can be represented as: Al3+ and its valency is +3.

Explanation:

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Answer 2

Explanation:

Heya!!

Here is your answer!!

• Atomic number of Al=13.

• Mass number of Al =27.

• Al3+=Removing 3 electrons from Al.

• Number of protons of Al3+= 13.

• Number of electrons of Al3+=13-3=10.

• Number of Neutrons of Al3+=13.

• Electronic configuration of Al+3:
• 2,8.

$1 {s}^{2} 2 {s}^{2} 2 {p}^{6}$

• Valency of Al is 3 as it has 3 electrons in its outermost shell.

Hope it helps u!!