Question

Atoms of element B from hcp lattice and those of elementA occupies two thirds of tetrahedral voids what isvthe formula of the compound from by these elements A & B

Answer 1

Answer:

Explanation: There are totla 6 atoms in hcp lattice... so B = 6

Now , tetrahedral voids will be = 2N = 2*6 = 12 But given , A = 2/3 * 2N = 2/3 * 12 = 8

hence , A = 8 & B=6

so Formula of the compound = A8B6 = A4B3

Answer 2

$\huge\boxed{\underline{\mathcal{\red{A}\green{N}\pink{S}\orange{W}\blue{E}\purple{R}}}}$

• ❤.. The number of tetralhedral voids formed is equal to twice the number of atoms of element B and only 2/3rd of these are occupied by the atoms of element A.
• ❤..Hence the ratio of the number of atoms of A and B is ${2×(2/3):1 or 4:3}$ and the formula of the compound is ${A4B3}$.