Math, asked by nirmohraut, 2 months ago

Atul earned 3,60,000 in the year 2010 and
3.88.800 in the year 2011.
(a) Find the percentage increase in his
annual income in the year 2011.
(b) If Atul's income in the year 2010 was
10% less than that in the previous year,
what was his annual income in the year
2009?​

Answers

Answered by enbyfeofyo
0

Answer:

(a) 8%

(b) 396000

Step-by-step explanation:

Income in 2010 = 360000

Income in 2011 = 388800

(a)

→ The increased income = 388800 - 360000 = 28800

→ The percentage increase in his annual income in 2010 is 28800/360000 = 8 %

(b)

Income in 2010 was 10% less than that in the previous year, year 2009

→ Income in 2009 - income in 2010 = 10% In come in 2010

→ Income in 2009 - 360000 = 10%*360000

→ Income in 2009 = 360000 + 36000 = 396000

Similar questions