Math, asked by jasvindarsinghkuttan, 4 months ago

please answer this its very urgent please irrelevant questions will be deleted and reported ​

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Answered by XxMrThankerxX
4

Answer:

Join DC and make an angle DCY equal to BDC.

Let CY intersect BX at A

ABC is the required triangle.

Case 1: Let AB > AC that is AB AC is given

Draw the base BC and at point B make an angle say XBC equal to the given angle.

Cut the line segment BD equal to AB AC from ray BX.

Join DC and draw the perpendicular bisector, say PQ of DC.

Let it intersect BX at a point A. Join AC.

Case 2: Let AB < AC that is AC AB is given

Draw the base BC and at point B make an angle say XBC equal to the given angle.

Cut line segment BD equal to AC AB from

theline BX extended on opposite side of

line segmentBC. Join DC and draw the perpendicular bisector, sayPQ of DC.

Let PQ intersect BX at A. Join AC

Answered by palak999690
2

Answer:

there is no brainlist here I can see and I answerd also.

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