Question

अवयव पाडा: 125y³ - 1

Answer 1

please check attachment

Answer 2

अवयव पाडा: 125y³ - 1

$125 {y}^{3} = {(5y)}^{3} \\ \\ 1= {1}^{3}$
${a}^{3} - {b}^{3} = (a-b)( {a}^{2} + ab+ {b}^{2} ) \\ \\ {(5y)}^{3} - {(1)}^{3} = (5y-1)\bigg[{(5y)}^{2} + (5y)(1) + {(1)}^{2} \bigg] \\ \\ = (5y-1)(25 {y}^{2} + 5y+ 1)$

अवयव

$125 {y}^{3} - 1= (5y-1)(25 {y}^{2} + 5y +1)$