Question

अवयव पाडा: $y^3+\frac{1}{8y^3}$

Answer 1

Solution :

$y^3+\frac{1}{8y^3}$

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we know that ,

a³+b³ = (a+b)(a ²-ab+b²)

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= y³ + (1/2y)³

= (y+1/2y)[(y²-y•(1/2y)+(1/2y)²]

=(y+1/2y)[y² -1/2 + 1/4y²]

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