Question

ax+by=2a-3b
bx-ay=3a+2b
solve by substitution method
​

Answer 1

Answer:

Given

Step-by-step explanation:

ax+by-2a+3b=0...............................(1)+

bx-ay=3a+2b....................................(2)

from equation (2) ,

bx-ay-3a-2b=0............................(3)

multiplying equation (1) by b and equation (2) by a

abx+b^2y-2ab+3b^2=0.......................(4)

abx-a^2y-3a^2-2ab=0...........................(5)a

subtracting eq (5) from (4)

abx+b^2y-2ab+3b^2=0

-abx+a^2y+3a^2+2ab=0

---------------------------------------

0+y(a^2+b^2)+3(a^2+b^2)=0

(a^2+b^2)(y+3)=0

y+3=0

y=-3

put in equation 1 ,

ax-3b-2a+3b=0

ax-2a=0

a(x-2)=0

x-2=0

x=2

Hope it helps

Mrk me as BRAINLIEST