(B)
27tr2
4tr
2 Tr3
(D)
Given that HCF (156, 78) = 78, LCM (156, 78) is
(A) 156
(B) 78
9 156 x 78
(D) 156 x 2
Areas of two similar triangles are in the
corresponding sides of these triangles are in the
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The LCM of the given numbers = 156
Step-by-step explanation:
First no. = 156
Second no. = 78
HCF of two numbers = 78
We know that for the given two numbers,
⇒ HCF × LCM = ×
⇒ 78 × LCM = 156 × 78
⇒ LCM = 156
Thus the LCM of the given numbers = 156
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