Question

(b-3) (b-5) evaluate​

Answer 1

Step-by-step explanation:

(b-3) (b-5)

b^2 - 5b - 3b + 15

b^2 - 8b +15

Answer 2

Given,

(b-3)(b-5)=0

To find,

Evaluate the given expression.

Solution,

(b-3)(b-5)

We will multiply each term of the first bracket with each term of the second bracket.

⇒  b(b-5)-3(b-5)

⇒  b²-5b-3b+15=0

⇒  b²-8b+15=0

Thus after evaluating, we obtained a quadratic equation having two roots.

On Evaluation of (b-3)(b-5) we get, b²-8b+15=0