Question

b. A force act for a 0.1s on a body of mass 1.2 Kg initially at rest. The force then
ceases to act and the body moves through 2m in the next ls. Find the magnitude
of force.
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Answer 1

Answer:

u = 0m/s

t = 0.1s

s = 2m

Now, s = ut + 1/2at²

2 = 1/2a(0.1)²

4 = 0.01a

a = 400m/s²

Now, m = 1.2kg

F = ma

F = 1.2 x 400

F = 480N

Hope it helps you!!