B
A->
Three identical blocks of mass
2kg each are connected by ideal
strings and one of block is applied
by a force 12N.The setup is kept
on a smooth horizontal
surface. Then. Normal from the
ground on Block A has the value (
Take g = 10 m/s^2)
Answers
Answered by
0
Answer:
Given,
Mass of A, B and C m
a
=m
b
=m
c
=2kg
Acceleration of system, a=
(m
a
+m
b
+m
c
)
F
=
3m
F
=
3×2
2
=
3
1
m/s
2
Tension between B and C, gives acceleration to block C of mass 2kg
T=m
c
a=2
3
1
=
3
2
N
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