Physics, asked by ar3715447p7hsgn, 3 months ago

B
A->
Three identical blocks of mass
2kg each are connected by ideal
strings and one of block is applied
by a force 12N.The setup is kept
on a smooth horizontal
surface. Then. Normal from the
ground on Block A has the value (
Take g = 10 m/s^2)​

Answers

Answered by ssurajprasad77
0

Answer:

Given,

Mass of A, B and C m

a

=m

b

=m

c

=2kg

Acceleration of system, a=

(m

a

+m

b

+m

c

)

F

=

3m

F

=

3×2

2

=

3

1

m/s

2

Tension between B and C, gives acceleration to block C of mass 2kg

T=m

c

a=2

3

1

=

3

2

N

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