b c = a-2b+3C
2
= 。
GF8-14
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Answer:
Given a,b,c are in GP let the common ratio be r.
Therefore, b=a.r,c=a.r
2
Also, a,2b,3c are in AP.
⇒2(2b)=4b=a+3c
⇒4.a.r=a+3.a.r
2
i.e. 3r
2
−4.r+1=0
⇒r=1,
3
1
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