Question

b c = a-2b+3C
2
= 。
GF8-14​

Answer 1

Answer:

Given a,b,c are in GP let the common ratio be r.

Therefore, b=a.r,c=a.r

2

Also, a,2b,3c are in AP.

⇒2(2b)=4b=a+3c

⇒4.a.r=a+3.a.r

2

i.e. 3r

2

−4.r+1=0

⇒r=1,

3

1