(b) Calculate the force exerted by the earth on the moon. Take the mass of the early
Me = 6 x 1024 kg and the mass of the moon M. = 7.4 x 1022 kg. The distance between the
earth and the moon is 3.84 x 105 km. Also, G = 6.7 x 10-11 Nm²/kg. 31
Answers
Answered by
11
Hi Dear:)
Answer :- 2.017 X 10^20 N
Explanation :- In the attachment
Thanks:)
Attachments:
Answered by
6
Mass of the Earth, Me = 6x10^24kg
Mass of the Moon, Mm = 7.4x10^22kg
Distance, d = 3.84x10^8m
G = 6.7x10^-11Nm^2/kg
F=GxMexMm / d^2
= (6.7x10^-11) x (6x10^24) x (7.4x10^22) / (3.84x10^8)^2
= 6.7 x 6 x 7.4 x 10^-11 + 24 + 22 / (3.84 x 3.84) x 10^16
= 6.7 x 6 x 7.4 x 10^-11 + 46 -16 / (3.84 x 3.84 )
= 6.7 x 6 x 7.4 x 10^19 / (3.84 x 3.84)
= 67 x 6 x 74 x 10^21 x 100 x 100 / (384 x 384) x 100 x 100
= 67 x 6 x 74 x 10^21 / 384 x 384
= 67 x 74 x 10^21 / 64 x 384
= 4958 x 10^21 / 24576
= 2479 x 10^21 / 12288
= 2479 x 10 x 10^20 / 12288
= 24790 x 10^21 / 12288
[Dividing 24790/12288]
= 2.01 x 10^21 N
Mass of the Moon, Mm = 7.4x10^22kg
Distance, d = 3.84x10^8m
G = 6.7x10^-11Nm^2/kg
F=GxMexMm / d^2
= (6.7x10^-11) x (6x10^24) x (7.4x10^22) / (3.84x10^8)^2
= 6.7 x 6 x 7.4 x 10^-11 + 24 + 22 / (3.84 x 3.84) x 10^16
= 6.7 x 6 x 7.4 x 10^-11 + 46 -16 / (3.84 x 3.84 )
= 6.7 x 6 x 7.4 x 10^19 / (3.84 x 3.84)
= 67 x 6 x 74 x 10^21 x 100 x 100 / (384 x 384) x 100 x 100
= 67 x 6 x 74 x 10^21 / 384 x 384
= 67 x 74 x 10^21 / 64 x 384
= 4958 x 10^21 / 24576
= 2479 x 10^21 / 12288
= 2479 x 10 x 10^20 / 12288
= 24790 x 10^21 / 12288
[Dividing 24790/12288]
= 2.01 x 10^21 N
Similar questions