Question

(b) Calculate the fundamental frequency of
H 35Cl if its force constant is 480 Nm-1​

Answer 1

Answer:

frequency (s-1)

ii) wavenumber (cm-1)

My attempt:

μH35Cl = 1.627 x 10^-27 kg

v = 1/2π x (480.5kg m s^-2/1.627 x 10^-27 kg)^1/2

v = 0.1592 x (2.953 x 10^29 m s^-2)^1/2

v = 0.1592 x (5.434 x 10^14 s^-1)

v = 8.651 x 10^13 s^-1

wavenumber = 2.886 x 10^3 cm^-1

hope it helps you...

Answer 2

The frequency of the given molecule is v = 8.651 x 10^13 s^-1.

Explanation:

We are given the force constant F = 480 Nm-1

We have to find the Frequency  

Solution:

μH35Cl = 1.627 x 10^-27 kg

v = 1/2π x (480.5kg m s^-2 / 1.627 x 10^-27 kg)^1/2

v = 0.1592 x (2.953 x 10^29 m s^-2)^1/2

v = 0.1592 x (5.434 x 10^14 s^-1)

v = 8.651 x 10^13 s^-1