(b) From the sum of 4a2-6a+3 and -4a²-7a+5 subtract 3a²-8a+6.
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Sum of 4a2 + 3 – 8a and 9a – 7
= 4a2 + 3 – 8a + 9a – 7 = 4a2 + a – 4
∴ (4a2 + a – 4) – (-5a2 – 3a + 1)
= 4a2 + a – 4 + 5a2 + 3a – 1
= 4a2 + 5a2 + a + 3a – 4 – 1
= 9a2 + 4a – 5
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