Question

b) Identify oxidant and reductant from the following reaction: 1) 2 H2 S + SO, 3 Su+ 2 H2O п) MnO2 + 4HCI MnCl2 + 2H2O + Cl2 A​

Answer 1

Explanation:





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Question



Identify the substance oxidized,substance reduced ,oxidizing agent and reducing agent :

MnO2+4HCl→MnCl2+2H2O+Cl2

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Solution



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                             MnO2+4HCl⟶MnCl2+2H2O+Cl2

Oxidation state:   +4               −1             +2                            0

Increase in oxidation state = Oxidation ⇒

As chlorine increases from −1⟶0⇒ (Oxidation of HCl) 

Decrease in oxidation state = Reduction ⇒ As manganese decreases from +4→+2⇒ (Reduction of MnO2)

⇒MnO2 is reduced, HCl is oxidized, MnO2 is oxidizing agent, HCl is reducing agent.