Question

(b) if 1.71g of sugar (molar mass=342) are dissolved in 500ml of an
aqueous solution at 300K. what will be its osmotic pressure?​

Answer 1

Answer:

Explanation:

Given: Wt. of solute (w)=1.71g

Molar mass of solute (m)=342

Volume of solution (v)=500ml=0.5lt

Temperature (T)=300K

Gas constant (R)=0.0821ltatmK  −1  mol  −1

 Osmotic pressure (π)=  mV wRT

​ =  342×0.5

1.71×0.0821×300

​ =0.25atm

Thus, Osmotic pressure of the solution is 0.25atm

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