Math, asked by shahmukund2009, 9 days ago

- b. If 6 sin A - 5 cos A = 0, find the values of cos A and cot A.​

Answers

Answered by sourishsarkarkgec
3

Answer:

cosA = 6/√61 , cotA = 6/5 .

Step-by-step explanation:

6 sin A - 5 cos A=0

=> 6 sin A = 5 cos A

=> sinA/ cos A= 5/6

=> tanA = 5/6

sec A = √(1 +(5/6)²

= √(1+ 25/36)

=√(61/36)

= √61/6

cosA = 6/√61 , cotA = 6/5 .

Answered by chandan454380
2

Answer:

value of cotA = 6/5

value of cosA = 6/√61

explanation:

6sinA-5cosA=0 => cosA/sinA = 6/5 => cotA = 6/5

tanA=5/6 =>sec^2 A = 1+ tan^2 A =>sec^2 A = 1+ 25/36 => sec^2 A = 61/36 => secA = √61/ 6 => cosA = 6/√61

value of cotA = 6/5

value of cosA = 6/√61

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