बाइनरी टो हेक्साडेसिमल
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Answer:
it is a question of chemistry
Answer:
Step 1: Write down the binary number and group the digits (0’s and 1’s) in sets of four. Start doing this from the right. If the leftmost group doesn’t have enough digits to make up a set of four, add extra 0’s to make a group.
Step 2: Write 8, 4, 2 and 1 below each group. These are the weights of the positions or place holders in the number (23, 22, 21 and 20).
Step 3: Every group of four in binary will give you one digit in hexadecimal. Multiply the 8, 4, 2 and 1’s by the digit above.
Step 4: Add the products within each set of four. Write the sums below the groups they belong to.
Step 5: The digits you get from the sums in each group will give you the hexadecimal number, from left to right.
Now, let’s apply these steps to, for example, the binary number (10101010)2
Step 1: 10101010 has eight digits and therefore can be grouped in sets of four without adding 0’s.
Think of the number as (1010)(1010)
Step 2: Write 8, 4, 2 and 1 below each group.
1010 1010
8421 8421
Step 3: Multiply the 8, 4, 2 and 1’s with the digit above.
1010 1010
8421 8421
8020 8020
Step 4: Add the products within each set of four.
In the first group, 8 + 2 = 10
In the second group, 8 + 2 = 10
Write these digits below the groups they belong to.
1010 1010
8421 8421
8020 8020
10 10
Step 5: Notice that, in order to represent values above 9, letters will be used. 10 is represented as the letter A in the hexadecimal system. Therefore, (10101010)2 = (AA)16