Math, asked by sahilkirti101, 1 month ago

ब्रैकेट टू एक्स स्क्वायर माइनस फाइव आइक्यू ब्रैकेट क्लोज स्क्वायर​

Answers

Answered by kunjvoracrvcom
0

Answer:

25y^{6}-20x^{2} y^{3}+4x^{4}

Step-by-step explanation:

(2x^{2}-5y^{3})^{2}\\(-5y^{3}+2x^{2})^{2}\\(-5y^{3}+2x^{2})(-5y^{3}+2x^{2})\\-5(-5y^{3}+2x^{2})*y^{3}+2(-5y^{3}+2x^{2})*x^{2} \\25y^{6}-10x^{2} y^{3}+2(-5y^{3}+2x^{2})*x^{2} \\25y^{6}-10x^{2} y^{3}-10x^{2} y^{3}+4x^{4}\\25y^{6}-20x^{2} y^{3}+4x^{4}

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