Math, asked by salman4125, 1 year ago

b
x {}^{2}  + 14x + 48 \: solve

Answers

Answered by bazelasaleem
1

x²+14x+48=0

x²+14x=-48

x²+7*2x+7²=-48+7²

(x+7)²=-48+49

(x+7)²=1

x+7=√1

x+7=1                    OR     x+7=-1

x=1-7                               x=-1-7

x=6                                 x=-8

(∝,β)=(6,-8)

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