The projectile is projected at 10 m/s by making an angle 60 with horizontal after some time it's velocity makes an angle of 30 to horizontal it's speed at this instant is
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Vertical = 10 x sin 60=5√3
Horizontal = 10 x cos 60 = 5 m/s
In a projectile horizontally components of velocity remains constant.
So,
=>10cos60°=Vcos30°
=>V=10cos60°sec30°
=>10/√3.
I hope this will help You !!
Horizontal = 10 x cos 60 = 5 m/s
In a projectile horizontally components of velocity remains constant.
So,
=>10cos60°=Vcos30°
=>V=10cos60°sec30°
=>10/√3.
I hope this will help You !!
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