Babu deposited a certain Amount in a bank which gives 10% simple interest anually. After two years, he got 400 rupees interest, if he deposited the same amount in another bank giving 10% compounded interest anually. How much interest he would have got?
Answers
Answered by
6
principal=p
r=10%
time=2y
SI=400rps
SI=p*r*t*/100
400=p*10*2/100
400=1/5p
p=400*5
p=2000
therefore, principal=2000rps
CA=p(1+r/100)^t
=2000(1+10/100)^2
=2000(110/100)^2
=2000*110/100*110/100
=2420
CI= CA-P
=24200-2000
=242rps (and)
r=10%
time=2y
SI=400rps
SI=p*r*t*/100
400=p*10*2/100
400=1/5p
p=400*5
p=2000
therefore, principal=2000rps
CA=p(1+r/100)^t
=2000(1+10/100)^2
=2000(110/100)^2
=2000*110/100*110/100
=2420
CI= CA-P
=24200-2000
=242rps (and)
Answered by
2
Answer:
Equation for finding simple interest :-
P×r/100×n
P means the starting amount
r means the rate of interest
n means the number of year
to find answer for this question=
P×10/100×2=400
=400/2=200
=200× 100/10
=2000
i.e he deposited 2000 rupees
Then he deposited the same amount in an another bank giving 10% compounded annually
so the equation=
P(1+r/100)^n
so 2000(1+10/100)^2
=2000×110/100×110/100
=2420 rupees
To find the answer 2420-2400= 20 rupees
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