Question

Baby A 150g ball travelling, at. 30m/s Strikes
the palm of a player's hand and and is stopped
in 0:05 Second - Find the force exerted by the
ball on hand
​

Answer 1

Given :

Mass of ball = 150g = 0.15kg

Initial velocity = 30m/s

Final velocity = zero

Time interval = 0.05s

To Find :

Force exerted by the ball on hand.

Solution :

❒ As per newton's second law of motion, force is measured as the rate of change of linear momentum$.$

• F = dp / dt

We know that momentum is defined as the product of mass and velocity.

• F = m dv / dt

• Force is a polar vector quantity having both magnitude as well as direction.

• It can be positive, negative or zero.

• SI unit : N

By substituting the given values,

➠ F = m dv / dt

➠ F = 0.15 × 30/0.05

➠ F = 0.15 × 600

➠ F = 90 N

Answer 2

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Given :

Mass of ball = 150g = 0.15kg

Initial velocity = 30m/s

Final velocity = zero

Time interval = 0.05s

To Find :

Force exerted by the ball on hand.

Solution :

As per newton's second law of motion, force is measured as the rate of change of linear momentum..

F = dp / dt

We know that momentum is defined as the product of mass and velocity.

F = m dv / dt

• Force is a polar vector quantity having both magnitude as well as direction.

• It can be positive, negative or zero.

• SI unit : N

By substituting the given values,

➠ F = m dv / dt

➠ F = 0.15 × 30/0.05

➠ F = 0.15 × 600

➠ F = 90 N